for what value of a would the following system of equations have an infinite number of solutions?2x - y = 8 6x - 3y = 41 A: 2 B: 6 C:8 D:24 E:32
2x - y = 8
6x - 3y = 4a. Multiply the top equation by 3, to give 6x - 3y = 24. This is almost identical with the bottom equation, except for constants. Forthe system to have an infinite number of solution, the constants must be equal. Hence, 4a = 24, and thus a = 6. |

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